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13w^2=9w
We move all terms to the left:
13w^2-(9w)=0
a = 13; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·13·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*13}=\frac{0}{26} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*13}=\frac{18}{26} =9/13 $
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